4c^2-4c+1=9

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Solution for 4c^2-4c+1=9 equation:


Simplifying
4c2 + -4c + 1 = 9

Reorder the terms:
1 + -4c + 4c2 = 9

Solving
1 + -4c + 4c2 = 9

Solving for variable 'c'.

Reorder the terms:
1 + -9 + -4c + 4c2 = 9 + -9

Combine like terms: 1 + -9 = -8
-8 + -4c + 4c2 = 9 + -9

Combine like terms: 9 + -9 = 0
-8 + -4c + 4c2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-2 + -1c + c2) = 0

Factor a trinomial.
4((-1 + -1c)(2 + -1c)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-1 + -1c)' equal to zero and attempt to solve: Simplifying -1 + -1c = 0 Solving -1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -1c = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -1c = 0 + 1 -1c = 0 + 1 Combine like terms: 0 + 1 = 1 -1c = 1 Divide each side by '-1'. c = -1 Simplifying c = -1

Subproblem 2

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Solution

c = {-1, 2}

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